Closest Equal Element Queries
You receive a circular array nums and an array queries.
For each query i, you have to determine the following:
- The minimum distance between the element at index
queries[i]and any other indexjin the circular array, wherenums[j] == nums[queries[i]]. If no such index exists, the answer for that query should be -1.
Produce an array answer of the same size as queries, where answer[i] represents the result for query i.
Input: nums = [1,3,1,4,1,3,2], queries = [0,3,5]
Output: [2,-1,3]
Explanation:
-
Query 0: The element at
queries[0] = 0isnums[0] = 1. The nearest index with the same value is 2, and the distance between them is 2. -
Query 1: The element at
queries[1] = 3isnums[3] = 4. No other index contains 4, so the result is -1. -
Query 2: The element at
queries[2] = 5isnums[5] = 3. The nearest index with the same value is 1, and the distance between them is 3 (following the circular path:5 -> 6 -> 0 -> 1).
Input: nums = [1,2,3,4], queries = [0,1,2,3]
Output: [-1,-1,-1,-1]
Explanation: Each value in nums is unique, so no index shares the same value as the queried element. This results in -1 for all queries.
Constraints
1 <= queries.length <= nums.length <= 10^51 <= nums[i] <= 10^60 <= queries[i] < nums.length
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