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Finding 3-Digit Even Numbers

Easy

You receive an integer array digits , where each element is a digit. The array may contain duplicates.

You need to determine all the unique integers that follow the given requirements:

  • The integer consists of the concatenation of three elements from digits in any arbitrary order.

  • The integer does not have leading zeros .

  • The integer is even .

For example, if the given digits were [1, 2, 3] , integers 132 and 312 follow the requirements.

Produce a sorted array of the unique integers.

Example 1

Input: digits = [2,1,3,0]

Output: [102,120,130,132,210,230,302,310,312,320]

Explanation: All the possible integers that follow the requirements are in the output array.

Notice that there are no odd integers or integers with leading zeros.

Example 2

Input: digits = [2,2,8,8,2]

Output: [222,228,282,288,822,828,882]

Explanation: The same digit can be used as many times as it appears in digits.

In this example, the digit 8 is used twice each time in 288, 828, and 882.

Example 3

Input: digits = [3,7,5]

Output: []

Explanation: No even integers can be formed using the given digits.

Constraints

  • 3 <= digits.length <= 100
  • 0 <= digits[i] <= 9

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