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Maximum Difference Between Even and Odd Frequency I

Easy

You receive a string s consisting of lowercase English letters.

Your task is to find the maximum difference diff = freq(a1) - freq(a2) between the frequency of characters a1 and a2 in the text such that:

  • a1 has an odd frequency in the text.

  • a2 has an even frequency in the text.

Produce this maximum difference.

Example 1

Input: s = "aaaaabbc"

Output: 3

Explanation:

  • The character 'a' has an odd frequency of 5, and 'b' has an even frequency of 2.

  • The maximum difference is 5 - 2 = 3.

Example 2

Input: s = "abcabcab"

Output: 1

Explanation:

  • The character 'a' has an odd frequency of 3, and 'c' has an even frequency of 2.

  • The maximum difference is 3 - 2 = 1.

Constraints

  • 3 <= s.length <= 100
  • s consists only of lowercase English letters.
  • s contains at least one character with an odd frequency and one with an even frequency.

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