Skip to main content
impol.dev

Maximum Fruits Harvested After at Most K Steps

Hard

Fruits are available at some positions on an infinite x-axis. You receive a 2D integer array fruits where fruits[i] = [position i, amount i ] depicts amount i fruits at the position position i. fruits is already sorted by position i in ascending order, and each position i is unique.

You are also given an integer startPos and an integer k. Initially, you are at the position startPos. From any position, you can either walk to the left or right. It takes one step to move one unit on the x-axis, and you can walk at most k steps in total. For every position you reach, you harvest all the fruits at that position, and the fruits will disappear from that position.

Produce the maximum total number of fruits you can harvest.

Example 1

Original illustrative diagram 1 for Maximum Fruits Harvested After at Most K Steps

Input: fruits = [[2,8],[6,3],[8,6]], startPos = 5, k = 4

Output: 9

Explanation: The optimal way is to:

  • Move right to position 6 and harvest 3 fruits

  • Move right to position 8 and harvest 6 fruits

You moved 3 steps and harvested 3 + 6 = 9 fruits in total.

Example 2

Original illustrative diagram 2 for Maximum Fruits Harvested After at Most K Steps

Input: fruits = [[0,9],[4,1],[5,7],[6,2],[7,4],[10,9]], startPos = 5, k = 4

Output: 14

Explanation: You can move at most k = 4 steps, so you cannot reach position 0 nor 10.

The optimal way is to:

  • Harvest the 7 fruits at the starting position 5

  • Move left to position 4 and harvest 1 fruit

  • Move right to position 6 and harvest 2 fruits

  • Move right to position 7 and harvest 4 fruits

You moved 1 + 3 = 4 steps and harvested 7 + 1 + 2 + 4 = 14 fruits in total.

Example 3

Original illustrative diagram 3 for Maximum Fruits Harvested After at Most K Steps

Input: fruits = [[0,3],[6,4],[8,5]], startPos = 3, k = 2

Output: 0

Explanation: You can move at most k = 2 steps and cannot reach any position with fruits.

Constraints

  • 1 <= fruits.length <= 10^5
  • fruits[i].length == 2
  • 0 <= startPos, position i <= 2 * 10^5
  • position i-1 < position i for any i > 0 (0-indexed)
  • 1 <= amount i <= 10^4
  • 0 <= k <= 2 * 10^5

Did this problem appear in one of your interviews?

Responses stay private.

Acceptance rate: 0%

© 2026 impol.dev. All rights reserved.PrivacyTerms